Thanks, Dan
One other thing I'm interested is that
I've observed that when you return a stall time with SIMICS_RETRY_TIME,
the same transactions will come before "ruby_operate" next cyle.
I'm wonderign about that:
if ruby use SIMICS_unstall_proc to unstall the processor, will be last
stalled transaction come to "ruby_operate" again.
or it just simply graduate?
Thanks.
在2008-04-05,"Dan Gibson" <degibson@xxxxxxxx> 写道:
That is exactly how ruby implements it. I don't know if its the only
way, but it works well.
Regards,
Dan
pathscale@xxxxxxx wrote:
> Thanks, Dan.
> But I wonder how ruby implement it.
> Is it by using API SIM_time_post_cycle in function "runRubyEventQueue" ?
> Is it the only way to wake up ruby every SIMICS_RUBY_MULTIPLIER cycles
> and run it indepently?
> Thanks
>
> 在2008-04-05,"Dan Gibson" <degibson@xxxxxxxx> 写道:
>
> No, but Ruby runs every SIMICS_RUBY_MULTIPLIER cycles independently of
> whether any new memory requests are presented to Ruby.
>
> Regards,
> Dan
>
> pathscale@xxxxxxx wrote:
> > Thanks.
> > Does it mean that even you stall a memory transaction with stall time
> > 200000000000
> > It will come to timing-model again next cycle, anyway?
> >
> > 在2008-04-04,"Dan Gibson" <degibson@xxxxxxxx> 写道:
> >
> > Often, a memory stall time is not known at request-time. In this
> > case, Ruby stalls Simics for a long long long time, but un-stalls
> > it when Ruby determines its coherence actions have been completed.
> >
> > Regards,
> > Dan
> >
> > pathscale wrote:
> >> Hi,
> >> I'm studying ruby's core and I'm curious about how a memory
> >> transaction can be returned with stall time like this:
> >> { Miss , SIMICS_STALL_TIME},
> >> which is to say an infinite stall time.
> >> I don't know in what condition this is supposed to happen.
> >> Thanks
> >>
> >>
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