Re: [Gems-users] Stall time

[pathscale@xxxxxxx]

 Thanks Greg

 

Is this "explicitly unstall" done at SimicsProcessor::hitCallback ?

 

After the unstall, will the stalled transaction come to timing model again or it just graduated quitely.

 

Thanks

 

 

 

在2008-04-05，"Greg Byrd" <gbyrd@xxxxxxxx> 写道：
> No, it will stall. The point is to give it a very long time to stall -- 
> longer than you think the memory operation will take. When the memory 
> operation is done (e.g, a couple hundred cycles later), then the 
> processor is explicitly unstalled.
>
> ...Greg
>
>
> pathscale@xxxxxxx wrote:
> > Thanks.
> > Does it mean that even you stall a memory transaction with stall time 
> > 200000000000
> > It will come to timing-model again next cycle, anyway?
> >
> > 在2008-04-04，"Dan Gibson" <degibson@xxxxxxxx> 写道：
> >
> >     Often, a memory stall time is not known at request-time. In this
> >     case, Ruby stalls Simics for a long long long time, but un-stalls
> >     it when Ruby determines its coherence actions have been completed.
> >
> >     Regards,
> >     Dan
> >
> >     pathscale wrote:
> >>     Hi,
> >>     I'm studying ruby's core and I'm curious about how a memory
> >>     transaction can be returned with stall time like this:
> >>     { Miss , SIMICS_STALL_TIME},
> >>     which is to say an infinite stall time.
> >>     I don't know in what condition this is supposed to happen.
> >>     Thanks
> >>
> >>
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