Re: [Gems-users] Regarding L2 miss rate

[sparsh mittal ISU <sparsh@xxxxxxxxxxx>]

Hello All
Thanks a lot for your answer. I am spending a lot of time for finding the code portion in ruby, indicating a hit in L2. Would anyone point me out where does the hit to L2 can be found out and counted?
I will really appreciate the answer.
Thanks
Sparsh

On Tue, Mar 16, 2010 at 12:00 PM, Byn Choi <bynchoi1@xxxxxxxxxxxx> wrote:

I think you got it backwards. # of memory accesses seen by L2 should be the number of accesses _not_ satisfied by L1, i.e. L1Imiss+L1Dmiss.

I'm not sure if stock ruby actually collects {# of accesses coming out of cores}. As always, looking at the code is probably the surest way to find the definitive answer.

Byn

On Mar 16, 2010, at 11:47 AM, sparsh mittal ISU wrote:

Hello Byn

Thanks for the prompt reply.In terms of the stats reported by ruby, would you explain the term,
"{# of mem accesses actually seen by L2}".

My understanding is that, global l2 miss rate is what I found, namely, L2_misses/(L1Imiss+L1Dmiss).

Thanks

Sparsh

On Tue, Mar 16, 2010 at 11:30 AM, Byn Choi <bynchoi1@xxxxxxxxxxxx> wrote:

Global L2 miss rate : {# of L2 misses}/{# of all mem accesses coming out of cores}
Local L2 miss rate : {# of L2 misses}/{# of mem accesses actually seen by L2}

Reference: Computer Architecture: a Quantitative Approach by John Hennessy and David Patterson

Byn

On Mar 16, 2010, at 11:22 AM, sparsh mittal ISU wrote:

Hello List
I searched the previous list postings a lot, however could not definitely find out the answer. I wanted to know about L2 miss rate. Is it simply L2_misses/(L1Imiss+L1Dmiss) or something else?

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Thanks and Regards
Sparsh Mittal

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Thanks and Regards
Sparsh Mittal
Graduate Student
Electrical and Computer Engineering
Iowa State University, Iowa, USA

-- 
Thanks and Regards
Sparsh Mittal
Graduate Student
Electrical and Computer Engineering
Iowa State University, Iowa, USA