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Re: [condor-users] jobs die due to low free memory
- Date: Tue, 6 Apr 2004 10:53:25 -0500 (CDT)
- From: Jaime Frey <jfrey@xxxxxxxxxxx>
- Subject: Re: [condor-users] jobs die due to low free memory
On Tue, 6 Apr 2004, Anika Boehm wrote:
> By the way: the expression
> on_exit_remove = (ExitBySignal == True) && (ExitSignal != 4)
> doesn't release a successfully done job (ExitCode = 0) from the queue (at
> least not with condor-6.5.3@Solaris). The expression still evaluates to FALSE.
> It seems
> on_exit_remove = ExitCode =?= 0
> is the solution to my problem.
Your original expression says to let a job leave the queue if it dies with
a signal other than 4. This doesn't include normal program termination.
This is probably what you meant:
on_exit_remove = (ExitBySignal == True && ExitSignal == 4) == False
Since ExitSignal is only defined if ExitBySignal is True, you can use the
meta-not-equals operator to simplify the expression (like you did in your
second expression):
on_exit_remove = ExitSignal =!= 4
+------------------------------------+-------------------------------+
| Jaime Frey |There are 10 types of people in|
| jfrey@xxxxxxxxxxx |the world: Those who understand|
| http://www.cs.wisc.edu/~jfrey/ | binary, and those who don't |
+------------------------------------+-------------------------------+
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