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Is the address 0xff26e00 a physical or logical address? If you just
obtained the address from the program you need to first get the
physical address translation of it. The easiest way (that I can
think of) would be to issue a magic break point after you printed the
instruction, and ask simics for the translation (check the simics
reference manual on how to do this). Then you'd need to change the
physical address to the translated value. You might also want to
consider creating a new magic instruction that first puts the
physical address in a known register and then translates that address
on a magic reference (you'd also have to make sure you read/wrote a
value to that address beforehand so that simics can actually perform
the translation and find it in the processors TLB). Check out the
simics.net for more information.
phil
On Jan 17, 2007, at 1:15 PM, Dave Z. wrote:
Hi,
I'm trying to catch some accesses in ruby_operate (ruby.c) using
the following:
if ((mem_op->s.physical_address >= 0xff26e000) && (mem_op-
>s.physical_address < 0xff26e00f))
printf("Accessing physical address %x\n", mem_op-
>s.physical_address);
In my benchmarks, I have int* ptr (where ptr = ff26e000). But the
following accesses are not caught in ruby_operate:
ptr[0] = value;
x = ptr[1];
...
Is there something wrong with what I'm doing?
Thanks
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